-11(y-2)+6y=3(y+4)+2

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Solution for -11(y-2)+6y=3(y+4)+2 equation: 



-11(y-2)+6y=3(y+4)+2

We move all terms to the left:

-11(y-2)+6y-(3(y+4)+2)=0

We add all the numbers together, and all the variables

6y-11(y-2)-(3(y+4)+2)=0

We multiply parentheses

6y-11y-(3(y+4)+2)+22=0



We calculate terms in parentheses: -(3(y+4)+2), so:

3(y+4)+2

We multiply parentheses

3y+12+2

We add all the numbers together, and all the variables

3y+14

Back to the equation:

-(3y+14)



We add all the numbers together, and all the variables

-5y-(3y+14)+22=0

We get rid of parentheses

-5y-3y-14+22=0

We add all the numbers together, and all the variables

-8y+8=0

We move all terms containing y to the left, all other terms to the right

-8y=-8

y=-8/-8

y=1

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