-11(z+2)+4(4z-6)=4(z-3)+10

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Solution for -11(z+2)+4(4z-6)=4(z-3)+10 equation: 



-11(z+2)+4(4z-6)=4(z-3)+10

We move all terms to the left:

-11(z+2)+4(4z-6)-(4(z-3)+10)=0

We multiply parentheses

-11z+16z-(4(z-3)+10)-22-24=0



We calculate terms in parentheses: -(4(z-3)+10), so:

4(z-3)+10

We multiply parentheses

4z-12+10

We add all the numbers together, and all the variables

4z-2

Back to the equation:

-(4z-2)



We add all the numbers together, and all the variables

5z-(4z-2)-46=0

We get rid of parentheses

5z-4z+2-46=0

We add all the numbers together, and all the variables

z-44=0

We move all terms containing z to the left, all other terms to the right

z=44

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