-11+10-11+10(p+10)=4-5(2p+11)

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Solution for -11+10-11+10(p+10)=4-5(2p+11) equation: 



-11+10-11+10(p+10)=4-5(2p+11)

We move all terms to the left:

-11+10-11+10(p+10)-(4-5(2p+11))=0

We add all the numbers together, and all the variables

10(p+10)-(4-5(2p+11))-12=0

We multiply parentheses

10p-(4-5(2p+11))+100-12=0



We calculate terms in parentheses: -(4-5(2p+11)), so:

4-5(2p+11)

determiningTheFunctionDomain
-5(2p+11)+4

We multiply parentheses

-10p-55+4

We add all the numbers together, and all the variables

-10p-51

Back to the equation:

-(-10p-51)



We add all the numbers together, and all the variables

10p-(-10p-51)+88=0

We get rid of parentheses

10p+10p+51+88=0

We add all the numbers together, and all the variables

20p+139=0

We move all terms containing p to the left, all other terms to the right

20p=-139

p=-139/20

p=-6+19/20

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