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-11-5a=6a(5a+)
We move all terms to the left:
-11-5a-(6a(5a+))=0
We add all the numbers together, and all the variables
-5a-(6a(+5a))-11=0
We calculate terms in parentheses: -(6a(+5a)), so:determiningTheFunctionDomain -30a^2-5a-11=0
6a(+5a)
We multiply parentheses
30a^2
Back to the equation:
-(30a^2)
a = -30; b = -5; c = -11;
Δ = b2-4ac
Δ = -52-4·(-30)·(-11)
Δ = -1295
Delta is less than zero, so there is no solution for the equation
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