-110+20y+4=6(5y-3)-8

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Solution for -110+20y+4=6(5y-3)-8 equation: 



-110+20y+4=6(5y-3)-8

We move all terms to the left:

-110+20y+4-(6(5y-3)-8)=0

We add all the numbers together, and all the variables

20y-(6(5y-3)-8)-106=0



We calculate terms in parentheses: -(6(5y-3)-8), so:

6(5y-3)-8

We multiply parentheses

30y-18-8

We add all the numbers together, and all the variables

30y-26

Back to the equation:

-(30y-26)



We get rid of parentheses

20y-30y+26-106=0

We add all the numbers together, and all the variables

-10y-80=0

We move all terms containing y to the left, all other terms to the right

-10y=80

y=80/-10

y=-8

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