-110=-n-5(1+4n)

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Solution for -110=-n-5(1+4n) equation: 



-110=-n-5(1+4n)

We move all terms to the left:

-110-(-n-5(1+4n))=0

We add all the numbers together, and all the variables

-(-n-5(4n+1))-110=0



We calculate terms in parentheses: -(-n-5(4n+1)), so:

-n-5(4n+1)

We add all the numbers together, and all the variables

-1n-5(4n+1)

We multiply parentheses

-1n-20n-5

We add all the numbers together, and all the variables

-21n-5

Back to the equation:

-(-21n-5)



We get rid of parentheses

21n+5-110=0

We add all the numbers together, and all the variables

21n-105=0

We move all terms containing n to the left, all other terms to the right

21n=105

n=105/21

n=5

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