-119=3(4c-8)+1

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Solution for -119=3(4c-8)+1 equation:



-119=3(4c-8)+1
We move all terms to the left:
-119-(3(4c-8)+1)=0
We calculate terms in parentheses: -(3(4c-8)+1), so:
3(4c-8)+1
We multiply parentheses
12c-24+1
We add all the numbers together, and all the variables
12c-23
Back to the equation:
-(12c-23)
We get rid of parentheses
-12c+23-119=0
We add all the numbers together, and all the variables
-12c-96=0
We move all terms containing c to the left, all other terms to the right
-12c=96
c=96/-12
c=-8

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