-11v+1=5(v+5)-8(3+2v)

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Solution for -11v+1=5(v+5)-8(3+2v) equation: 



-11v+1=5(v+5)-8(3+2v)

We move all terms to the left:

-11v+1-(5(v+5)-8(3+2v))=0

We add all the numbers together, and all the variables

-11v-(5(v+5)-8(2v+3))+1=0



We calculate terms in parentheses: -(5(v+5)-8(2v+3)), so:

5(v+5)-8(2v+3)

We multiply parentheses

5v-16v+25-24

We add all the numbers together, and all the variables

-11v+1

Back to the equation:

-(-11v+1)



We get rid of parentheses

-11v+11v-1+1=0

We add all the numbers together, and all the variables

=0

v=0/1

v=0

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