-11x(x+26)-27(x+26)=15x-15

Solution for -11x(x+26)-27(x+26)=15x-15 equation:

-11x(x+26)-27(x+26)=15x-15

We move all terms to the left:

-11x(x+26)-27(x+26)-(15x-15)=0

We multiply parentheses

-11x^2-286x-27x-(15x-15)-702=0

We get rid of parentheses

-11x^2-286x-27x-15x+15-702=0

We add all the numbers together, and all the variables

-11x^2-328x-687=0

a = -11; b = -328; c = -687;
Δ = b2-4ac
Δ = -3282-4·(-11)·(-687)
Δ = 77356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{77356}=\sqrt{4*19339}=\sqrt{4}*\sqrt{19339}=2\sqrt{19339}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-328)-2\sqrt{19339}}{2*-11}=\frac{328-2\sqrt{19339}}{-22}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-328)+2\sqrt{19339}}{2*-11}=\frac{328+2\sqrt{19339}}{-22}
$