-11y=4(y-3)+6y=4y-12

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Solution for -11y=4(y-3)+6y=4y-12 equation: 



-11y=4(y-3)+6y=4y-12

We move all terms to the left:

-11y-(4(y-3)+6y)=0



We calculate terms in parentheses: -(4(y-3)+6y), so:

4(y-3)+6y

We add all the numbers together, and all the variables

6y+4(y-3)

We multiply parentheses

6y+4y-12

We add all the numbers together, and all the variables

10y-12

Back to the equation:

-(10y-12)



We get rid of parentheses

-11y-10y+12=0

We add all the numbers together, and all the variables

-21y+12=0

We move all terms containing y to the left, all other terms to the right

-21y=-12

y=-12/-21

y=4/7

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