-12(m+9)+8(3-10)=m+9+1-2(m-5)

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Solution for -12(m+9)+8(3-10)=m+9+1-2(m-5) equation:



-12(m+9)+8(3-10)=m+9+1-2(m-5)
We move all terms to the left:
-12(m+9)+8(3-10)-(m+9+1-2(m-5))=0
We add all the numbers together, and all the variables
-12(m+9)-(m+9+1-2(m-5))+8(-7)=0
We add all the numbers together, and all the variables
-12(m+9)-(m+9+1-2(m-5))-56=0
We multiply parentheses
-12m-(m+9+1-2(m-5))-108-56=0
We calculate terms in parentheses: -(m+9+1-2(m-5)), so:
m+9+1-2(m-5)
determiningTheFunctionDomain m-2(m-5)+9+1
We add all the numbers together, and all the variables
m-2(m-5)+10
We multiply parentheses
m-2m+10+10
We add all the numbers together, and all the variables
-1m+20
Back to the equation:
-(-1m+20)
We add all the numbers together, and all the variables
-12m-(-1m+20)-164=0
We get rid of parentheses
-12m+1m-20-164=0
We add all the numbers together, and all the variables
-11m-184=0
We move all terms containing m to the left, all other terms to the right
-11m=184
m=184/-11
m=-16+8/11

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