-12(x+2)+6(3x-5)=5(x-5)+13

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Solution for -12(x+2)+6(3x-5)=5(x-5)+13 equation: 



-12(x+2)+6(3x-5)=5(x-5)+13

We move all terms to the left:

-12(x+2)+6(3x-5)-(5(x-5)+13)=0

We multiply parentheses

-12x+18x-(5(x-5)+13)-24-30=0



We calculate terms in parentheses: -(5(x-5)+13), so:

5(x-5)+13

We multiply parentheses

5x-25+13

We add all the numbers together, and all the variables

5x-12

Back to the equation:

-(5x-12)



We add all the numbers together, and all the variables

6x-(5x-12)-54=0

We get rid of parentheses

6x-5x+12-54=0

We add all the numbers together, and all the variables

x-42=0

We move all terms containing x to the left, all other terms to the right

x=42

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