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-12(x-10)x=0
We multiply parentheses
-12x^2+120x=0
a = -12; b = 120; c = 0;
Δ = b2-4ac
Δ = 1202-4·(-12)·0
Δ = 14400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{14400}=120$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(120)-120}{2*-12}=\frac{-240}{-24} =+10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(120)+120}{2*-12}=\frac{0}{-24} =0 $
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