-12(x-19)=3(x+16)

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Solution for -12(x-19)=3(x+16) equation: 



-12(x-19)=3(x+16)

We move all terms to the left:

-12(x-19)-(3(x+16))=0

We multiply parentheses

-12x-(3(x+16))+228=0



We calculate terms in parentheses: -(3(x+16)), so:

3(x+16)

We multiply parentheses

3x+48

Back to the equation:

-(3x+48)



We get rid of parentheses

-12x-3x-48+228=0

We add all the numbers together, and all the variables

-15x+180=0

We move all terms containing x to the left, all other terms to the right

-15x=-180

x=-180/-15

x=+12

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