-12(x-2)+3x=1/2(x+6)+2

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Solution for -12(x-2)+3x=1/2(x+6)+2 equation: 



-12(x-2)+3x=1/2(x+6)+2

We move all terms to the left:

-12(x-2)+3x-(1/2(x+6)+2)=0



Domain of the equation: 2(x+6)+2)!=0

x∈R



We add all the numbers together, and all the variables

3x-12(x-2)-(1/2(x+6)+2)=0

We multiply parentheses

3x-12x-(1/2(x+6)+2)+24=0

We multiply all the terms by the denominator


3x*2(x+6)+2)-12x*2(x+6)+2)-(1+24*2(x+6)+2)=0

We add all the numbers together, and all the variables

3x*2(x+6)+2)-12x*2(x+6)+2)-(1+24*2(x=0

Wy multiply elements

6x^2(x+2)-12x*2(x+6)+24*2(x+2)-(1=0

We add all the numbers together, and all the variables

6x^2(x+2)-12x*2(x+6)+24*2(x+2)=0

Wy multiply elements

6x^2(x+2)-24x^2(x+48x(x=0

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