-12(x-3)-4=3(-2x+4)-60

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Solution for -12(x-3)-4=3(-2x+4)-60 equation: 



-12(x-3)-4=3(-2x+4)-60

We move all terms to the left:

-12(x-3)-4-(3(-2x+4)-60)=0

We multiply parentheses

-12x-(3(-2x+4)-60)+36-4=0



We calculate terms in parentheses: -(3(-2x+4)-60), so:

3(-2x+4)-60

We multiply parentheses

-6x+12-60

We add all the numbers together, and all the variables

-6x-48

Back to the equation:

-(-6x-48)



We add all the numbers together, and all the variables

-12x-(-6x-48)+32=0

We get rid of parentheses

-12x+6x+48+32=0

We add all the numbers together, and all the variables

-6x+80=0

We move all terms containing x to the left, all other terms to the right

-6x=-80

x=-80/-6

x=13+1/3

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