-12(y+2)+6(3y-3)=5(y-3)+13

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Solution for -12(y+2)+6(3y-3)=5(y-3)+13 equation: 



-12(y+2)+6(3y-3)=5(y-3)+13

We move all terms to the left:

-12(y+2)+6(3y-3)-(5(y-3)+13)=0

We multiply parentheses

-12y+18y-(5(y-3)+13)-24-18=0



We calculate terms in parentheses: -(5(y-3)+13), so:

5(y-3)+13

We multiply parentheses

5y-15+13

We add all the numbers together, and all the variables

5y-2

Back to the equation:

-(5y-2)



We add all the numbers together, and all the variables

6y-(5y-2)-42=0

We get rid of parentheses

6y-5y+2-42=0

We add all the numbers together, and all the variables

y-40=0

We move all terms containing y to the left, all other terms to the right

y=40

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