-12+22(v-32)=38v-45(9v-43)

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Solution for -12+22(v-32)=38v-45(9v-43) equation: 



-12+22(v-32)=38v-45(9v-43)

We move all terms to the left:

-12+22(v-32)-(38v-45(9v-43))=0

We multiply parentheses

22v-(38v-45(9v-43))-704-12=0



We calculate terms in parentheses: -(38v-45(9v-43)), so:

38v-45(9v-43)

We multiply parentheses

38v-405v+1935

We add all the numbers together, and all the variables

-367v+1935

Back to the equation:

-(-367v+1935)



We add all the numbers together, and all the variables

22v-(-367v+1935)-716=0

We get rid of parentheses

22v+367v-1935-716=0

We add all the numbers together, and all the variables

389v-2651=0

We move all terms containing v to the left, all other terms to the right

389v=2651

v=2651/389

v=6+317/389

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