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-12+2x=5-3(2x-5)
We move all terms to the left:
-12+2x-(5-3(2x-5))=0
We calculate terms in parentheses: -(5-3(2x-5)), so:We get rid of parentheses
5-3(2x-5)
determiningTheFunctionDomain -3(2x-5)+5
We multiply parentheses
-6x+15+5
We add all the numbers together, and all the variables
-6x+20
Back to the equation:
-(-6x+20)
2x+6x-20-12=0
We add all the numbers together, and all the variables
8x-32=0
We move all terms containing x to the left, all other terms to the right
8x=32
x=32/8
x=4
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