-12+4v=6(v-2)

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Solution for -12+4v=6(v-2) equation: 



-12+4v=6(v-2)

We move all terms to the left:

-12+4v-(6(v-2))=0



We calculate terms in parentheses: -(6(v-2)), so:

6(v-2)

We multiply parentheses

6v-12

Back to the equation:

-(6v-12)



We get rid of parentheses

4v-6v+12-12=0

We add all the numbers together, and all the variables

-2v=0

v=0/-2

v=0

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