-12+8(x-5)=-4+3(5x-2)

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Solution for -12+8(x-5)=-4+3(5x-2) equation: 



-12+8(x-5)=-4+3(5x-2)

We move all terms to the left:

-12+8(x-5)-(-4+3(5x-2))=0

We multiply parentheses

8x-(-4+3(5x-2))-40-12=0



We calculate terms in parentheses: -(-4+3(5x-2)), so:

-4+3(5x-2)

determiningTheFunctionDomain
3(5x-2)-4

We multiply parentheses

15x-6-4

We add all the numbers together, and all the variables

15x-10

Back to the equation:

-(15x-10)



We add all the numbers together, and all the variables

8x-(15x-10)-52=0

We get rid of parentheses

8x-15x+10-52=0

We add all the numbers together, and all the variables

-7x-42=0

We move all terms containing x to the left, all other terms to the right

-7x=42

x=42/-7

x=-6

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