-12+8(x-5)=-4-3(5x-2)

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Solution for -12+8(x-5)=-4-3(5x-2) equation: 



-12+8(x-5)=-4-3(5x-2)

We move all terms to the left:

-12+8(x-5)-(-4-3(5x-2))=0

We multiply parentheses

8x-(-4-3(5x-2))-40-12=0



We calculate terms in parentheses: -(-4-3(5x-2)), so:

-4-3(5x-2)

determiningTheFunctionDomain
-3(5x-2)-4

We multiply parentheses

-15x+6-4

We add all the numbers together, and all the variables

-15x+2

Back to the equation:

-(-15x+2)



We add all the numbers together, and all the variables

8x-(-15x+2)-52=0

We get rid of parentheses

8x+15x-2-52=0

We add all the numbers together, and all the variables

23x-54=0

We move all terms containing x to the left, all other terms to the right

23x=54

x=54/23

x=2+8/23

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