-12+99x+98=-12(1-22x)-13(12x-20)

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Solution for -12+99x+98=-12(1-22x)-13(12x-20) equation: 



-12+99x+98=-12(1-22x)-13(12x-20)

We move all terms to the left:

-12+99x+98-(-12(1-22x)-13(12x-20))=0

We add all the numbers together, and all the variables

99x-(-12(-22x+1)-13(12x-20))-12+98=0

We add all the numbers together, and all the variables

99x-(-12(-22x+1)-13(12x-20))+86=0



We calculate terms in parentheses: -(-12(-22x+1)-13(12x-20)), so:

-12(-22x+1)-13(12x-20)

We multiply parentheses

264x-156x-12+260

We add all the numbers together, and all the variables

108x+248

Back to the equation:

-(108x+248)



We get rid of parentheses

99x-108x-248+86=0

We add all the numbers together, and all the variables

-9x-162=0

We move all terms containing x to the left, all other terms to the right

-9x=162

x=162/-9

x=-18

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