-12-2(5-3x)=6(-4x+3)-10x

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Solution for -12-2(5-3x)=6(-4x+3)-10x equation: 



-12-2(5-3x)=6(-4x+3)-10x

We move all terms to the left:

-12-2(5-3x)-(6(-4x+3)-10x)=0

We add all the numbers together, and all the variables

-2(-3x+5)-(6(-4x+3)-10x)-12=0

We multiply parentheses

6x-(6(-4x+3)-10x)-10-12=0



We calculate terms in parentheses: -(6(-4x+3)-10x), so:

6(-4x+3)-10x

We add all the numbers together, and all the variables

-10x+6(-4x+3)

We multiply parentheses

-10x-24x+18

We add all the numbers together, and all the variables

-34x+18

Back to the equation:

-(-34x+18)



We add all the numbers together, and all the variables

6x-(-34x+18)-22=0

We get rid of parentheses

6x+34x-18-22=0

We add all the numbers together, and all the variables

40x-40=0

We move all terms containing x to the left, all other terms to the right

40x=40

x=40/40

x=1

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