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-120=9.8+-4.9t^2
We move all terms to the left:
-120-(9.8+-4.9t^2)=0
We use the square of the difference formula
-(9.8-4.9t^2)-120=0
We get rid of parentheses
4.9t^2-9.8-120=0
We add all the numbers together, and all the variables
4.9t^2-129.8=0
a = 4.9; b = 0; c = -129.8;
Δ = b2-4ac
Δ = 02-4·4.9·(-129.8)
Δ = 2544.08
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{2544.08}}{2*4.9}=\frac{0-\sqrt{2544.08}}{9.8} =-\frac{\sqrt{}}{9.8} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{2544.08}}{2*4.9}=\frac{0+\sqrt{2544.08}}{9.8} =\frac{\sqrt{}}{9.8} $
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