-125=n-6(1+3n)

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Solution for -125=n-6(1+3n) equation: 



-125=n-6(1+3n)

We move all terms to the left:

-125-(n-6(1+3n))=0

We add all the numbers together, and all the variables

-(n-6(3n+1))-125=0



We calculate terms in parentheses: -(n-6(3n+1)), so:

n-6(3n+1)

We multiply parentheses

n-18n-6

We add all the numbers together, and all the variables

-17n-6

Back to the equation:

-(-17n-6)



We get rid of parentheses

17n+6-125=0

We add all the numbers together, and all the variables

17n-119=0

We move all terms containing n to the left, all other terms to the right

17n=119

n=119/17

n=7

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