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-126-3=4(-7p-6)*7p
We move all terms to the left:
-126-3-(4(-7p-6)*7p)=0
We add all the numbers together, and all the variables
-(4(-7p-6)*7p)-129=0
We calculate terms in parentheses: -(4(-7p-6)*7p), so:We get rid of parentheses
4(-7p-6)*7p
We multiply parentheses
-196p^2-168p
Back to the equation:
-(-196p^2-168p)
196p^2+168p-129=0
a = 196; b = 168; c = -129;
Δ = b2-4ac
Δ = 1682-4·196·(-129)
Δ = 129360
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{129360}=\sqrt{784*165}=\sqrt{784}*\sqrt{165}=28\sqrt{165}$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(168)-28\sqrt{165}}{2*196}=\frac{-168-28\sqrt{165}}{392} $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(168)+28\sqrt{165}}{2*196}=\frac{-168+28\sqrt{165}}{392} $
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