-127=3-5(4m-2)

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Solution for -127=3-5(4m-2) equation: 



-127=3-5(4m-2)

We move all terms to the left:

-127-(3-5(4m-2))=0



We calculate terms in parentheses: -(3-5(4m-2)), so:

3-5(4m-2)

determiningTheFunctionDomain
-5(4m-2)+3

We multiply parentheses

-20m+10+3

We add all the numbers together, and all the variables

-20m+13

Back to the equation:

-(-20m+13)



We get rid of parentheses

20m-13-127=0

We add all the numbers together, and all the variables

20m-140=0

We move all terms containing m to the left, all other terms to the right

20m=140

m=140/20

m=7

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