-128/4z=-8

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Solution for -128/4z=-8 equation: 



-128/4z=-8

We move all terms to the left:

-128/4z-(-8)=0



Domain of the equation: 4z!=0

z!=0/4

z!=0

z∈R



We add all the numbers together, and all the variables

-128/4z+8=0

We multiply all the terms by the denominator


8*4z-128=0

Wy multiply elements

32z-128=0

We move all terms containing z to the left, all other terms to the right

32z=128

z=128/32

z=4

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