-128=2x-4(3x+12)

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Solution for -128=2x-4(3x+12) equation: 



-128=2x-4(3x+12)

We move all terms to the left:

-128-(2x-4(3x+12))=0



We calculate terms in parentheses: -(2x-4(3x+12)), so:

2x-4(3x+12)

We multiply parentheses

2x-12x-48

We add all the numbers together, and all the variables

-10x-48

Back to the equation:

-(-10x-48)



We get rid of parentheses

10x+48-128=0

We add all the numbers together, and all the variables

10x-80=0

We move all terms containing x to the left, all other terms to the right

10x=80

x=80/10

x=8

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