-12=(3v+5)6v

Solution for -12=(3v+5)6v equation:

-12=(3v+5)6v

We move all terms to the left:

-12-((3v+5)6v)=0


We calculate terms in parentheses: -((3v+5)6v), so:

(3v+5)6v

We multiply parentheses

18v^2+30v

Back to the equation:

-(18v^2+30v)


We get rid of parentheses

-18v^2-30v-12=0

a = -18; b = -30; c = -12;
Δ = b2-4ac
Δ = -302-4·(-18)·(-12)
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-6}{2*-18}=\frac{24}{-36}
=-2/3
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+6}{2*-18}=\frac{36}{-36}
=-1
$