-12=(4/3)(2x-1)

Solution for -12=(4/3)(2x-1) equation:

-12=(4/3)(2x-1)

We move all terms to the left:

-12-((4/3)(2x-1))=0


Domain of the equation: 3)(2x-1))!=0

x∈R


We add all the numbers together, and all the variables

-((+4/3)(2x-1))-12=0

We multiply parentheses ..

-((+8x^2+4/3*-1))-12=0

We multiply all the terms by the denominator


-((+8x^2+4-12*3*-1))=0


We calculate terms in parentheses: -((+8x^2+4-12*3*-1)), so:

(+8x^2+4-12*3*-1)

We get rid of parentheses

8x^2+4-1-12*3*

We add all the numbers together, and all the variables

8x^2

Back to the equation:

-(8x^2)


a = -8; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-8)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-16}=0$