-12=-3(c-2)-3c

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Solution for -12=-3(c-2)-3c equation: 



-12=-3(c-2)-3c

We move all terms to the left:

-12-(-3(c-2)-3c)=0



We calculate terms in parentheses: -(-3(c-2)-3c), so:

-3(c-2)-3c

We add all the numbers together, and all the variables

-3c-3(c-2)

We multiply parentheses

-3c-3c+6

We add all the numbers together, and all the variables

-6c+6

Back to the equation:

-(-6c+6)



We get rid of parentheses

6c-6-12=0

We add all the numbers together, and all the variables

6c-18=0

We move all terms containing c to the left, all other terms to the right

6c=18

c=18/6

c=3

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