-12=3(j-16)+-18

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Solution for -12=3(j-16)+-18 equation: 



-12=3(j-16)+-18

We move all terms to the left:

-12-(3(j-16)+-18)=0

We use the square of the difference formula

-(3(j-16)-18)-12=0



We calculate terms in parentheses: -(3(j-16)-18), so:

3(j-16)-18

We multiply parentheses

3j-48-18

We add all the numbers together, and all the variables

3j-66

Back to the equation:

-(3j-66)



We get rid of parentheses

-3j+66-12=0

We add all the numbers together, and all the variables

-3j+54=0

We move all terms containing j to the left, all other terms to the right

-3j=-54

j=-54/-3

j=+18

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