-12=3u+3(u-2)

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Solution for -12=3u+3(u-2) equation: 



-12=3u+3(u-2)

We move all terms to the left:

-12-(3u+3(u-2))=0



We calculate terms in parentheses: -(3u+3(u-2)), so:

3u+3(u-2)

We multiply parentheses

3u+3u-6

We add all the numbers together, and all the variables

6u-6

Back to the equation:

-(6u-6)



We get rid of parentheses

-6u+6-12=0

We add all the numbers together, and all the variables

-6u-6=0

We move all terms containing u to the left, all other terms to the right

-6u=6

u=6/-6

u=-1

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