-12=6+(2/3)y

Solution for -12=6+(2/3)y equation:

-12=6+(2/3)y

We move all terms to the left:

-12-(6+(2/3)y)=0


Domain of the equation: 3)y)!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

-(6+(+2/3)y)-12=0

We multiply all the terms by the denominator


-(6+(+2-12*3)y)=0


We calculate terms in parentheses: -(6+(+2-12*3)y), so:

6+(+2-12*3)y

determiningTheFunctionDomain
(+2-12*3)y+6

We add all the numbers together, and all the variables

(-34)y+6

We multiply parentheses

-34y+6

Back to the equation:

-(-34y+6)


We get rid of parentheses

34y-6=0

We move all terms containing y to the left, all other terms to the right

34y=6

y=6/34

y=3/17