-12=8(y-4)-6y

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Solution for -12=8(y-4)-6y equation: 



-12=8(y-4)-6y

We move all terms to the left:

-12-(8(y-4)-6y)=0



We calculate terms in parentheses: -(8(y-4)-6y), so:

8(y-4)-6y

We add all the numbers together, and all the variables

-6y+8(y-4)

We multiply parentheses

-6y+8y-32

We add all the numbers together, and all the variables

2y-32

Back to the equation:

-(2y-32)



We get rid of parentheses

-2y+32-12=0

We add all the numbers together, and all the variables

-2y+20=0

We move all terms containing y to the left, all other terms to the right

-2y=-20

y=-20/-2

y=+10

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