-12d-6=-2d(d+3)-10d

Solution for -12d-6=-2d(d+3)-10d equation:

-12d-6=-2d(d+3)-10d

We move all terms to the left:

-12d-6-(-2d(d+3)-10d)=0


We calculate terms in parentheses: -(-2d(d+3)-10d), so:

-2d(d+3)-10d

We add all the numbers together, and all the variables

-10d-2d(d+3)

We multiply parentheses

-2d^2-10d-6d

We add all the numbers together, and all the variables

-2d^2-16d

Back to the equation:

-(-2d^2-16d)


We get rid of parentheses

2d^2+16d-12d-6=0

We add all the numbers together, and all the variables

2d^2+4d-6=0

a = 2; b = 4; c = -6;
Δ = b2-4ac
Δ = 42-4·2·(-6)
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-8}{2*2}=\frac{-12}{4}
=-3
$
$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+8}{2*2}=\frac{4}{4}
=1
$