-12h+3-10=-19+3(-2h-20)

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Solution for -12h+3-10=-19+3(-2h-20) equation: 



-12h+3-10=-19+3(-2h-20)

We move all terms to the left:

-12h+3-10-(-19+3(-2h-20))=0

We add all the numbers together, and all the variables

-12h-(-19+3(-2h-20))-7=0



We calculate terms in parentheses: -(-19+3(-2h-20)), so:

-19+3(-2h-20)

determiningTheFunctionDomain
3(-2h-20)-19

We multiply parentheses

-6h-60-19

We add all the numbers together, and all the variables

-6h-79

Back to the equation:

-(-6h-79)



We get rid of parentheses

-12h+6h+79-7=0

We add all the numbers together, and all the variables

-6h+72=0

We move all terms containing h to the left, all other terms to the right

-6h=-72

h=-72/-6

h=+12

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