-12j-6(2j-1)=-2(j-3)

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Solution for -12j-6(2j-1)=-2(j-3) equation: 



-12j-6(2j-1)=-2(j-3)

We move all terms to the left:

-12j-6(2j-1)-(-2(j-3))=0

We multiply parentheses

-12j-12j-(-2(j-3))+6=0



We calculate terms in parentheses: -(-2(j-3)), so:

-2(j-3)

We multiply parentheses

-2j+6

Back to the equation:

-(-2j+6)



We add all the numbers together, and all the variables

-24j-(-2j+6)+6=0

We get rid of parentheses

-24j+2j-6+6=0

We add all the numbers together, and all the variables

-22j=0

j=0/-22

j=0

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