-12p2+30p=0

Solution for -12p2+30p=0 equation:

-12p^2+30p=0

a = -12; b = 30; c = 0;
Δ = b2-4ac
Δ = 302-4·(-12)·0
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(30)-30}{2*-12}=\frac{-60}{-24}
=2+1/2
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(30)+30}{2*-12}=\frac{0}{-24}
=0
$