-12r+11=-r2

Solution for -12r+11=-r2 equation:

-12r+11=-r2

We move all terms to the left:

-12r+11-(-r2)=0

We add all the numbers together, and all the variables

-(-1r^2)-12r+11=0

We get rid of parentheses

1r^2-12r+11=0

We add all the numbers together, and all the variables

r^2-12r+11=0

a = 1; b = -12; c = +11;
Δ = b2-4ac
Δ = -122-4·1·11
Δ = 100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{100}=10$
$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-10}{2*1}=\frac{2}{2}
=1
$
$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+10}{2*1}=\frac{22}{2}
=11
$