-12v-58=-10(10v-12)-2

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Solution for -12v-58=-10(10v-12)-2 equation: 



-12v-58=-10(10v-12)-2

We move all terms to the left:

-12v-58-(-10(10v-12)-2)=0



We calculate terms in parentheses: -(-10(10v-12)-2), so:

-10(10v-12)-2

We multiply parentheses

-100v+120-2

We add all the numbers together, and all the variables

-100v+118

Back to the equation:

-(-100v+118)



We get rid of parentheses

-12v+100v-118-58=0

We add all the numbers together, and all the variables

88v-176=0

We move all terms containing v to the left, all other terms to the right

88v=176

v=176/88

v=2

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