-12x(10+2x)=-10

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Solution for -12x(10+2x)=-10 equation:



-12x(10+2x)=-10
We move all terms to the left:
-12x(10+2x)-(-10)=0
We add all the numbers together, and all the variables
-12x(2x+10)-(-10)=0
We add all the numbers together, and all the variables
-12x(2x+10)+10=0
We multiply parentheses
-24x^2-120x+10=0
a = -24; b = -120; c = +10;
Δ = b2-4ac
Δ = -1202-4·(-24)·10
Δ = 15360
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{15360}=\sqrt{1024*15}=\sqrt{1024}*\sqrt{15}=32\sqrt{15}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-120)-32\sqrt{15}}{2*-24}=\frac{120-32\sqrt{15}}{-48} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-120)+32\sqrt{15}}{2*-24}=\frac{120+32\sqrt{15}}{-48} $

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