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-12x(x-1)=-3(x-1)
We move all terms to the left:
-12x(x-1)-(-3(x-1))=0
We multiply parentheses
-12x^2+12x-(-3(x-1))=0
We calculate terms in parentheses: -(-3(x-1)), so:We get rid of parentheses
-3(x-1)
We multiply parentheses
-3x+3
Back to the equation:
-(-3x+3)
-12x^2+12x+3x-3=0
We add all the numbers together, and all the variables
-12x^2+15x-3=0
a = -12; b = 15; c = -3;
Δ = b2-4ac
Δ = 152-4·(-12)·(-3)
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-9}{2*-12}=\frac{-24}{-24} =1 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+9}{2*-12}=\frac{-6}{-24} =1/4 $
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