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-12x-(1/2x+4)+12=x-6(3x-13/3)
We move all terms to the left:
-12x-(1/2x+4)+12-(x-6(3x-13/3))=0
Domain of the equation: 2x+4)!=0We add all the numbers together, and all the variables
x∈R
-12x-(1/2x+4)-(x-6(+3x-13/3))+12=0
We get rid of parentheses
-12x-1/2x-(x-6(+3x-13/3))-4+12=0
We calculate fractions
-12x+()/6x^2+(-(x-6(+3x-13*2x)/6x^2-4+12=0
We calculate fractions
We do not support expression: x^4
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