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-12x^2+120-36x=0
a = -12; b = -36; c = +120;
Δ = b2-4ac
Δ = -362-4·(-12)·120
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{7056}=84$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-84}{2*-12}=\frac{-48}{-24} =+2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+84}{2*-12}=\frac{120}{-24} =-5 $
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