-12x2+x+1=0

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Solution for -12x2+x+1=0 equation:



-12x^2+x+1=0
a = -12; b = 1; c = +1;
Δ = b2-4ac
Δ = 12-4·(-12)·1
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-7}{2*-12}=\frac{-8}{-24} =1/3 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+7}{2*-12}=\frac{6}{-24} =-1/4 $

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