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-12x^2=-1200
We move all terms to the left:
-12x^2-(-1200)=0
We add all the numbers together, and all the variables
-12x^2+1200=0
a = -12; b = 0; c = +1200;
Δ = b2-4ac
Δ = 02-4·(-12)·1200
Δ = 57600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{57600}=240$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-240}{2*-12}=\frac{-240}{-24} =+10 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+240}{2*-12}=\frac{240}{-24} =-10 $
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