-12y(y+1)=0

Solution for -12y(y+1)=0 equation:

-12y(y+1)=0

We multiply parentheses

-12y^2-12y=0

a = -12; b = -12; c = 0;
Δ = b2-4ac
Δ = -122-4·(-12)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-12}{2*-12}=\frac{0}{-24}
=0
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+12}{2*-12}=\frac{24}{-24}
=-1
$